4(3z-2)-3(z-2)=61

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Solution for 4(3z-2)-3(z-2)=61 equation:


Simplifying
4(3z + -2) + -3(z + -2) = 61

Reorder the terms:
4(-2 + 3z) + -3(z + -2) = 61
(-2 * 4 + 3z * 4) + -3(z + -2) = 61
(-8 + 12z) + -3(z + -2) = 61

Reorder the terms:
-8 + 12z + -3(-2 + z) = 61
-8 + 12z + (-2 * -3 + z * -3) = 61
-8 + 12z + (6 + -3z) = 61

Reorder the terms:
-8 + 6 + 12z + -3z = 61

Combine like terms: -8 + 6 = -2
-2 + 12z + -3z = 61

Combine like terms: 12z + -3z = 9z
-2 + 9z = 61

Solving
-2 + 9z = 61

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 9z = 61 + 2

Combine like terms: -2 + 2 = 0
0 + 9z = 61 + 2
9z = 61 + 2

Combine like terms: 61 + 2 = 63
9z = 63

Divide each side by '9'.
z = 7

Simplifying
z = 7

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