4(3z-2)=2(3z-2)

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Solution for 4(3z-2)=2(3z-2) equation: 



4(3z-2)=2(3z-2)

We move all terms to the left:

4(3z-2)-(2(3z-2))=0

We multiply parentheses

12z-(2(3z-2))-8=0



We calculate terms in parentheses: -(2(3z-2)), so:

2(3z-2)

We multiply parentheses

6z-4

Back to the equation:

-(6z-4)



We get rid of parentheses

12z-6z+4-8=0

We add all the numbers together, and all the variables

6z-4=0

We move all terms containing z to the left, all other terms to the right

6z=4

z=4/6

z=2/3

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