4(3z-2)=2(n+1)

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Solution for 4(3z-2)=2(n+1) equation:


Simplifying
4(3z + -2) = 2(n + 1)

Reorder the terms:
4(-2 + 3z) = 2(n + 1)
(-2 * 4 + 3z * 4) = 2(n + 1)
(-8 + 12z) = 2(n + 1)

Reorder the terms:
-8 + 12z = 2(1 + n)
-8 + 12z = (1 * 2 + n * 2)
-8 + 12z = (2 + 2n)

Solving
-8 + 12z = 2 + 2n

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 12z = 2 + 8 + 2n

Combine like terms: -8 + 8 = 0
0 + 12z = 2 + 8 + 2n
12z = 2 + 8 + 2n

Combine like terms: 2 + 8 = 10
12z = 10 + 2n

Divide each side by '12'.
z = 0.8333333333 + 0.1666666667n

Simplifying
z = 0.8333333333 + 0.1666666667n

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