4(3z-2)=28

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Solution for 4(3z-2)=28 equation: 



4(3z-2)=28

We move all terms to the left:

4(3z-2)-(28)=0

We multiply parentheses

12z-8-28=0

We add all the numbers together, and all the variables

12z-36=0

We move all terms containing z to the left, all other terms to the right

12z=36

z=36/12

z=3

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