4(3z-2)=3(2z-6)

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Solution for 4(3z-2)=3(2z-6) equation: 



4(3z-2)=3(2z-6)

We move all terms to the left:

4(3z-2)-(3(2z-6))=0

We multiply parentheses

12z-(3(2z-6))-8=0



We calculate terms in parentheses: -(3(2z-6)), so:

3(2z-6)

We multiply parentheses

6z-18

Back to the equation:

-(6z-18)



We get rid of parentheses

12z-6z+18-8=0

We add all the numbers together, and all the variables

6z+10=0

We move all terms containing z to the left, all other terms to the right

6z=-10

z=-10/6

z=-1+2/3

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