4(3z-2)=z-7

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Solution for 4(3z-2)=z-7 equation: 



4(3z-2)=z-7

We move all terms to the left:

4(3z-2)-(z-7)=0

We multiply parentheses

12z-(z-7)-8=0

We get rid of parentheses

12z-z+7-8=0

We add all the numbers together, and all the variables

11z-1=0

We move all terms containing z to the left, all other terms to the right

11z=1

z=1/11

z=1/11

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