4(3z-7)+(5z+1)=56

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Solution for 4(3z-7)+(5z+1)=56 equation:


Simplifying
4(3z + -7) + (5z + 1) = 56

Reorder the terms:
4(-7 + 3z) + (5z + 1) = 56
(-7 * 4 + 3z * 4) + (5z + 1) = 56
(-28 + 12z) + (5z + 1) = 56

Reorder the terms:
-28 + 12z + (1 + 5z) = 56

Remove parenthesis around (1 + 5z)
-28 + 12z + 1 + 5z = 56

Reorder the terms:
-28 + 1 + 12z + 5z = 56

Combine like terms: -28 + 1 = -27
-27 + 12z + 5z = 56

Combine like terms: 12z + 5z = 17z
-27 + 17z = 56

Solving
-27 + 17z = 56

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '27' to each side of the equation.
-27 + 27 + 17z = 56 + 27

Combine like terms: -27 + 27 = 0
0 + 17z = 56 + 27
17z = 56 + 27

Combine like terms: 56 + 27 = 83
17z = 83

Divide each side by '17'.
z = 4.882352941

Simplifying
z = 4.882352941

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