4(3z-7)+3(5z+1)=56

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Solution for 4(3z-7)+3(5z+1)=56 equation:


Simplifying
4(3z + -7) + 3(5z + 1) = 56

Reorder the terms:
4(-7 + 3z) + 3(5z + 1) = 56
(-7 * 4 + 3z * 4) + 3(5z + 1) = 56
(-28 + 12z) + 3(5z + 1) = 56

Reorder the terms:
-28 + 12z + 3(1 + 5z) = 56
-28 + 12z + (1 * 3 + 5z * 3) = 56
-28 + 12z + (3 + 15z) = 56

Reorder the terms:
-28 + 3 + 12z + 15z = 56

Combine like terms: -28 + 3 = -25
-25 + 12z + 15z = 56

Combine like terms: 12z + 15z = 27z
-25 + 27z = 56

Solving
-25 + 27z = 56

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + 27z = 56 + 25

Combine like terms: -25 + 25 = 0
0 + 27z = 56 + 25
27z = 56 + 25

Combine like terms: 56 + 25 = 81
27z = 81

Divide each side by '27'.
z = 3

Simplifying
z = 3

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