4(4+1)+u=3(4-2)+6

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Solution for 4(4+1)+u=3(4-2)+6 equation:



4(4+1)+u=3(4-2)+6
We move all terms to the left:
4(4+1)+u-(3(4-2)+6)=0
We add all the numbers together, and all the variables
u+45-(32+6)=0
We add all the numbers together, and all the variables
u+7=0
We move all terms containing u to the left, all other terms to the right
u=-7

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