4(4+2c)=48

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Solution for 4(4+2c)=48 equation: 



4(4+2c)=48

We move all terms to the left:

4(4+2c)-(48)=0

We add all the numbers together, and all the variables

4(2c+4)-48=0

We multiply parentheses

8c+16-48=0

We add all the numbers together, and all the variables

8c-32=0

We move all terms containing c to the left, all other terms to the right

8c=32

c=32/8

c=4

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