4(4+3b)=88

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Solution for 4(4+3b)=88 equation: 



4(4+3b)=88

We move all terms to the left:

4(4+3b)-(88)=0

We add all the numbers together, and all the variables

4(3b+4)-88=0

We multiply parentheses

12b+16-88=0

We add all the numbers together, and all the variables

12b-72=0

We move all terms containing b to the left, all other terms to the right

12b=72

b=72/12

b=6

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