4(4+c)=3(c-4)

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Solution for 4(4+c)=3(c-4) equation: 


Simplifying
4(4 + c) = 3(c + -4)
(4 * 4 + c * 4) = 3(c + -4)
(16 + 4c) = 3(c + -4)

Reorder the terms:
16 + 4c = 3(-4 + c)
16 + 4c = (-4 * 3 + c * 3)
16 + 4c = (-12 + 3c)

Solving
16 + 4c = -12 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
16 + 4c + -3c = -12 + 3c + -3c

Combine like terms: 4c + -3c = 1c
16 + 1c = -12 + 3c + -3c

Combine like terms: 3c + -3c = 0
16 + 1c = -12 + 0
16 + 1c = -12

Add '-16' to each side of the equation.
16 + -16 + 1c = -12 + -16

Combine like terms: 16 + -16 = 0
0 + 1c = -12 + -16
1c = -12 + -16

Combine like terms: -12 + -16 = -28
1c = -28

Divide each side by '1'.
c = -28

Simplifying
c = -28

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