4(4+c)=3(c-5)

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Solution for 4(4+c)=3(c-5) equation: 


Simplifying
4(4 + c) = 3(c + -5)
(4 * 4 + c * 4) = 3(c + -5)
(16 + 4c) = 3(c + -5)

Reorder the terms:
16 + 4c = 3(-5 + c)
16 + 4c = (-5 * 3 + c * 3)
16 + 4c = (-15 + 3c)

Solving
16 + 4c = -15 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
16 + 4c + -3c = -15 + 3c + -3c

Combine like terms: 4c + -3c = 1c
16 + 1c = -15 + 3c + -3c

Combine like terms: 3c + -3c = 0
16 + 1c = -15 + 0
16 + 1c = -15

Add '-16' to each side of the equation.
16 + -16 + 1c = -15 + -16

Combine like terms: 16 + -16 = 0
0 + 1c = -15 + -16
1c = -15 + -16

Combine like terms: -15 + -16 = -31
1c = -31

Divide each side by '1'.
c = -31

Simplifying
c = -31

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