4(4+s)=2(3s-1)-14

Solution for 4(4+s)=2(3s-1)-14 equation:

4(4+s)=2(3s-1)-14

We move all terms to the left:

4(4+s)-(2(3s-1)-14)=0

We add all the numbers together, and all the variables

4(s+4)-(2(3s-1)-14)=0

We multiply parentheses

4s-(2(3s-1)-14)+16=0


We calculate terms in parentheses: -(2(3s-1)-14), so:

2(3s-1)-14

We multiply parentheses

6s-2-14

We add all the numbers together, and all the variables

6s-16

Back to the equation:

-(6s-16)


We get rid of parentheses

4s-6s+16+16=0

We add all the numbers together, and all the variables

-2s+32=0

We move all terms containing s to the left, all other terms to the right

-2s=-32

s=-32/-2

s=+16