4(4+y)=3(1-3y)

Solution for 4(4+y)=3(1-3y) equation:

4(4+y)=3(1-3y)

We move all terms to the left:

4(4+y)-(3(1-3y))=0

We add all the numbers together, and all the variables

4(y+4)-(3(-3y+1))=0

We multiply parentheses

4y-(3(-3y+1))+16=0


We calculate terms in parentheses: -(3(-3y+1)), so:

3(-3y+1)

We multiply parentheses

-9y+3

Back to the equation:

-(-9y+3)


We get rid of parentheses

4y+9y-3+16=0

We add all the numbers together, and all the variables

13y+13=0

We move all terms containing y to the left, all other terms to the right

13y=-13

y=-13/13

y=-1