4(4+y)=32

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Solution for 4(4+y)=32 equation: 



4(4+y)=32

We move all terms to the left:

4(4+y)-(32)=0

We add all the numbers together, and all the variables

4(y+4)-32=0

We multiply parentheses

4y+16-32=0

We add all the numbers together, and all the variables

4y-16=0

We move all terms containing y to the left, all other terms to the right

4y=16

y=16/4

y=4

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