4(4-2t)+(3-t)+9(t)=19

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Solution for 4(4-2t)+(3-t)+9(t)=19 equation: 



4(4-2t)+(3-t)+9(t)=19

We move all terms to the left:

4(4-2t)+(3-t)+9(t)-(19)=0

We add all the numbers together, and all the variables

4(-2t+4)+(-1t+3)+9t-19=0

We add all the numbers together, and all the variables

9t+4(-2t+4)+(-1t+3)-19=0

We multiply parentheses

9t-8t+(-1t+3)+16-19=0

We get rid of parentheses

9t-8t-1t+3+16-19=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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