4(4-3)=6(m+1)

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Solution for 4(4-3)=6(m+1) equation: 



4(4-3)=6(m+1)

We move all terms to the left:

4(4-3)-(6(m+1))=0

We add all the numbers together, and all the variables

-(6(m+1))+41=0



We calculate terms in parentheses: -(6(m+1)), so:

6(m+1)

We multiply parentheses

6m+6

Back to the equation:

-(6m+6)



We get rid of parentheses

-6m-6+41=0

We add all the numbers together, and all the variables

-6m+35=0

We move all terms containing m to the left, all other terms to the right

-6m=-35

m=-35/-6

m=5+5/6

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