4(4-b)=3(2b+2)

Solution for 4(4-b)=3(2b+2) equation:

Simplifying
4(4 + -1b) = 3(2b + 2)
(4 * 4 + -1b * 4) = 3(2b + 2)
(16 + -4b) = 3(2b + 2)

Reorder the terms:
16 + -4b = 3(2 + 2b)
16 + -4b = (2 * 3 + 2b * 3)
16 + -4b = (6 + 6b)

Solving
16 + -4b = 6 + 6b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-6b' to each side of the equation.
16 + -4b + -6b = 6 + 6b + -6b

Combine like terms: -4b + -6b = -10b
16 + -10b = 6 + 6b + -6b

Combine like terms: 6b + -6b = 0
16 + -10b = 6 + 0
16 + -10b = 6

Add '-16' to each side of the equation.
16 + -16 + -10b = 6 + -16

Combine like terms: 16 + -16 = 0
0 + -10b = 6 + -16
-10b = 6 + -16

Combine like terms: 6 + -16 = -10
-10b = -10

Divide each side by '-10'.
b = 1

Simplifying
b = 1