4(4-n)=3(2n+2)

Solution for 4(4-n)=3(2n+2) equation:

4(4-n)=3(2n+2)

We move all terms to the left:

4(4-n)-(3(2n+2))=0

We add all the numbers together, and all the variables

4(-1n+4)-(3(2n+2))=0

We multiply parentheses

-4n-(3(2n+2))+16=0


We calculate terms in parentheses: -(3(2n+2)), so:

3(2n+2)

We multiply parentheses

6n+6

Back to the equation:

-(6n+6)


We get rid of parentheses

-4n-6n-6+16=0

We add all the numbers together, and all the variables

-10n+10=0

We move all terms containing n to the left, all other terms to the right

-10n=-10

n=-10/-10

n=1