4(4-x)+6(x-1)=x+200

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Solution for 4(4-x)+6(x-1)=x+200 equation: 



4(4-x)+6(x-1)=x+200

We move all terms to the left:

4(4-x)+6(x-1)-(x+200)=0

We add all the numbers together, and all the variables

4(-1x+4)+6(x-1)-(x+200)=0

We multiply parentheses

-4x+6x-(x+200)+16-6=0

We get rid of parentheses

-4x+6x-x-200+16-6=0

We add all the numbers together, and all the variables

x-190=0

We move all terms containing x to the left, all other terms to the right

x=190

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