4(4-y)-28=20y-6(2+4y)

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Solution for 4(4-y)-28=20y-6(2+4y) equation:


Simplifying
4(4 + -1y) + -28 = 20y + -6(2 + 4y)
(4 * 4 + -1y * 4) + -28 = 20y + -6(2 + 4y)
(16 + -4y) + -28 = 20y + -6(2 + 4y)

Reorder the terms:
16 + -28 + -4y = 20y + -6(2 + 4y)

Combine like terms: 16 + -28 = -12
-12 + -4y = 20y + -6(2 + 4y)
-12 + -4y = 20y + (2 * -6 + 4y * -6)
-12 + -4y = 20y + (-12 + -24y)

Reorder the terms:
-12 + -4y = -12 + 20y + -24y

Combine like terms: 20y + -24y = -4y
-12 + -4y = -12 + -4y

Add '12' to each side of the equation.
-12 + 12 + -4y = -12 + 12 + -4y

Combine like terms: -12 + 12 = 0
0 + -4y = -12 + 12 + -4y
-4y = -12 + 12 + -4y

Combine like terms: -12 + 12 = 0
-4y = 0 + -4y
-4y = -4y

Add '4y' to each side of the equation.
-4y + 4y = -4y + 4y

Combine like terms: -4y + 4y = 0
0 = -4y + 4y

Combine like terms: -4y + 4y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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