4(40-8x)=19x+2-5x

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Solution for 4(40-8x)=19x+2-5x equation: 



4(40-8x)=19x+2-5x

We move all terms to the left:

4(40-8x)-(19x+2-5x)=0

We add all the numbers together, and all the variables

4(-8x+40)-(14x+2)=0

We multiply parentheses

-32x-(14x+2)+160=0

We get rid of parentheses

-32x-14x-2+160=0

We add all the numbers together, and all the variables

-46x+158=0

We move all terms containing x to the left, all other terms to the right

-46x=-158

x=-158/-46

x=3+10/23

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