4(4X-7)-6=4(x-3)+32

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Solution for 4(4X-7)-6=4(x-3)+32 equation: 



4(4X-7)-6=4(X-3)+32

We move all terms to the left:

4(4X-7)-6-(4(X-3)+32)=0

We multiply parentheses

16X-(4(X-3)+32)-28-6=0



We calculate terms in parentheses: -(4(X-3)+32), so:

4(X-3)+32

We multiply parentheses

4X-12+32

We add all the numbers together, and all the variables

4X+20

Back to the equation:

-(4X+20)



We add all the numbers together, and all the variables

16X-(4X+20)-34=0

We get rid of parentheses

16X-4X-20-34=0

We add all the numbers together, and all the variables

12X-54=0

We move all terms containing X to the left, all other terms to the right

12X=54

X=54/12

X=4+1/2

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