4(4a-3)-(a-5)=-52

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Solution for 4(4a-3)-(a-5)=-52 equation: 



4(4a-3)-(a-5)=-52

We move all terms to the left:

4(4a-3)-(a-5)-(-52)=0

We add all the numbers together, and all the variables

4(4a-3)-(a-5)+52=0

We multiply parentheses

16a-(a-5)-12+52=0

We get rid of parentheses

16a-a+5-12+52=0

We add all the numbers together, and all the variables

15a+45=0

We move all terms containing a to the left, all other terms to the right

15a=-45

a=-45/15

a=-3

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