4(4b+2)=6(1-3b)+2

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Solution for 4(4b+2)=6(1-3b)+2 equation: 



4(4b+2)=6(1-3b)+2

We move all terms to the left:

4(4b+2)-(6(1-3b)+2)=0

We add all the numbers together, and all the variables

4(4b+2)-(6(-3b+1)+2)=0

We multiply parentheses

16b-(6(-3b+1)+2)+8=0



We calculate terms in parentheses: -(6(-3b+1)+2), so:

6(-3b+1)+2

We multiply parentheses

-18b+6+2

We add all the numbers together, and all the variables

-18b+8

Back to the equation:

-(-18b+8)



We get rid of parentheses

16b+18b-8+8=0

We add all the numbers together, and all the variables

34b=0

b=0/34

b=0

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