4(4b+3)+2b=3b-33

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Solution for 4(4b+3)+2b=3b-33 equation: 



4(4b+3)+2b=3b-33

We move all terms to the left:

4(4b+3)+2b-(3b-33)=0

We add all the numbers together, and all the variables

2b+4(4b+3)-(3b-33)=0

We multiply parentheses

2b+16b-(3b-33)+12=0

We get rid of parentheses

2b+16b-3b+33+12=0

We add all the numbers together, and all the variables

15b+45=0

We move all terms containing b to the left, all other terms to the right

15b=-45

b=-45/15

b=-3

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