4(4b-4)-3=-99

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Solution for 4(4b-4)-3=-99 equation: 



4(4b-4)-3=-99

We move all terms to the left:

4(4b-4)-3-(-99)=0

We add all the numbers together, and all the variables

4(4b-4)+96=0

We multiply parentheses

16b-16+96=0

We add all the numbers together, and all the variables

16b+80=0

We move all terms containing b to the left, all other terms to the right

16b=-80

b=-80/16

b=-5

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