4(4c+5)=4(5c+1)

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Solution for 4(4c+5)=4(5c+1) equation: 



4(4c+5)=4(5c+1)

We move all terms to the left:

4(4c+5)-(4(5c+1))=0

We multiply parentheses

16c-(4(5c+1))+20=0



We calculate terms in parentheses: -(4(5c+1)), so:

4(5c+1)

We multiply parentheses

20c+4

Back to the equation:

-(20c+4)



We get rid of parentheses

16c-20c-4+20=0

We add all the numbers together, and all the variables

-4c+16=0

We move all terms containing c to the left, all other terms to the right

-4c=-16

c=-16/-4

c=+4

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