4(4c-2)-160=5(12c+4)

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Solution for 4(4c-2)-160=5(12c+4) equation: 



4(4c-2)-160=5(12c+4)

We move all terms to the left:

4(4c-2)-160-(5(12c+4))=0

We multiply parentheses

16c-(5(12c+4))-8-160=0



We calculate terms in parentheses: -(5(12c+4)), so:

5(12c+4)

We multiply parentheses

60c+20

Back to the equation:

-(60c+20)



We add all the numbers together, and all the variables

16c-(60c+20)-168=0

We get rid of parentheses

16c-60c-20-168=0

We add all the numbers together, and all the variables

-44c-188=0

We move all terms containing c to the left, all other terms to the right

-44c=188

c=188/-44

c=-4+3/11

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