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4(4c-3)=2(5c+1)
We move all terms to the left:
4(4c-3)-(2(5c+1))=0
We multiply parentheses
16c-(2(5c+1))-12=0
We calculate terms in parentheses: -(2(5c+1)), so:We get rid of parentheses
2(5c+1)
We multiply parentheses
10c+2
Back to the equation:
-(10c+2)
16c-10c-2-12=0
We add all the numbers together, and all the variables
6c-14=0
We move all terms containing c to the left, all other terms to the right
6c=14
c=14/6
c=2+1/3
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