4(4c-3)=2(5c+18)

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Solution for 4(4c-3)=2(5c+18) equation:



4(4c-3)=2(5c+18)
We move all terms to the left:
4(4c-3)-(2(5c+18))=0
We multiply parentheses
16c-(2(5c+18))-12=0
We calculate terms in parentheses: -(2(5c+18)), so:
2(5c+18)
We multiply parentheses
10c+36
Back to the equation:
-(10c+36)
We get rid of parentheses
16c-10c-36-12=0
We add all the numbers together, and all the variables
6c-48=0
We move all terms containing c to the left, all other terms to the right
6c=48
c=48/6
c=8

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