4(4c-3)=6(3c-2)

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Solution for 4(4c-3)=6(3c-2) equation: 



4(4c-3)=6(3c-2)

We move all terms to the left:

4(4c-3)-(6(3c-2))=0

We multiply parentheses

16c-(6(3c-2))-12=0



We calculate terms in parentheses: -(6(3c-2)), so:

6(3c-2)

We multiply parentheses

18c-12

Back to the equation:

-(18c-12)



We get rid of parentheses

16c-18c+12-12=0

We add all the numbers together, and all the variables

-2c=0

c=0/-2

c=0

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