4(4c-5)=2(6c+12)

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Solution for 4(4c-5)=2(6c+12) equation: 



4(4c-5)=2(6c+12)

We move all terms to the left:

4(4c-5)-(2(6c+12))=0

We multiply parentheses

16c-(2(6c+12))-20=0



We calculate terms in parentheses: -(2(6c+12)), so:

2(6c+12)

We multiply parentheses

12c+24

Back to the equation:

-(12c+24)



We get rid of parentheses

16c-12c-24-20=0

We add all the numbers together, and all the variables

4c-44=0

We move all terms containing c to the left, all other terms to the right

4c=44

c=44/4

c=11

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