4(4d+2)=12(6d-4)

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Solution for 4(4d+2)=12(6d-4) equation:



4(4d+2)=12(6d-4)
We move all terms to the left:
4(4d+2)-(12(6d-4))=0
We multiply parentheses
16d-(12(6d-4))+8=0
We calculate terms in parentheses: -(12(6d-4)), so:
12(6d-4)
We multiply parentheses
72d-48
Back to the equation:
-(72d-48)
We get rid of parentheses
16d-72d+48+8=0
We add all the numbers together, and all the variables
-56d+56=0
We move all terms containing d to the left, all other terms to the right
-56d=-56
d=-56/-56
d=1

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