4(4i-5)=5(3i+4)

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Solution for 4(4i-5)=5(3i+4) equation: 



4(4i-5)=5(3i+4)

We move all terms to the left:

4(4i-5)-(5(3i+4))=0

We multiply parentheses

16i-(5(3i+4))-20=0



We calculate terms in parentheses: -(5(3i+4)), so:

5(3i+4)

We multiply parentheses

15i+20

Back to the equation:

-(15i+20)



We get rid of parentheses

16i-15i-20-20=0

We add all the numbers together, and all the variables

i-40=0

We move all terms containing i to the left, all other terms to the right

i=40

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