4(4n+3)-6=6n-2(1-4n)

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Solution for 4(4n+3)-6=6n-2(1-4n) equation: 



4(4n+3)-6=6n-2(1-4n)

We move all terms to the left:

4(4n+3)-6-(6n-2(1-4n))=0

We add all the numbers together, and all the variables

4(4n+3)-(6n-2(-4n+1))-6=0

We multiply parentheses

16n-(6n-2(-4n+1))+12-6=0



We calculate terms in parentheses: -(6n-2(-4n+1)), so:

6n-2(-4n+1)

We multiply parentheses

6n+8n-2

We add all the numbers together, and all the variables

14n-2

Back to the equation:

-(14n-2)



We add all the numbers together, and all the variables

16n-(14n-2)+6=0

We get rid of parentheses

16n-14n+2+6=0

We add all the numbers together, and all the variables

2n+8=0

We move all terms containing n to the left, all other terms to the right

2n=-8

n=-8/2

n=-4

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