4(4n-4)=11n+3(n-4)

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Solution for 4(4n-4)=11n+3(n-4) equation: 



4(4n-4)=11n+3(n-4)

We move all terms to the left:

4(4n-4)-(11n+3(n-4))=0

We multiply parentheses

16n-(11n+3(n-4))-16=0



We calculate terms in parentheses: -(11n+3(n-4)), so:

11n+3(n-4)

We multiply parentheses

11n+3n-12

We add all the numbers together, and all the variables

14n-12

Back to the equation:

-(14n-12)



We get rid of parentheses

16n-14n+12-16=0

We add all the numbers together, and all the variables

2n-4=0

We move all terms containing n to the left, all other terms to the right

2n=4

n=4/2

n=2

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