4(4t+1)-6=t-(t+1)

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Solution for 4(4t+1)-6=t-(t+1) equation:



4(4t+1)-6=t-(t+1)
We move all terms to the left:
4(4t+1)-6-(t-(t+1))=0
We multiply parentheses
16t-(t-(t+1))+4-6=0
We calculate terms in parentheses: -(t-(t+1)), so:
t-(t+1)
We get rid of parentheses
t-t-1
We add all the numbers together, and all the variables
-1
Back to the equation:
-(-1)
We add all the numbers together, and all the variables
16t-1=0
We move all terms containing t to the left, all other terms to the right
16t=1
t=1/16
t=1/16

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