4(4x+1)+3=1+x

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Solution for 4(4x+1)+3=1+x equation: 



4(4x+1)+3=1+x

We move all terms to the left:

4(4x+1)+3-(1+x)=0

We add all the numbers together, and all the variables

4(4x+1)-(x+1)+3=0

We multiply parentheses

16x-(x+1)+4+3=0

We get rid of parentheses

16x-x-1+4+3=0

We add all the numbers together, and all the variables

15x+6=0

We move all terms containing x to the left, all other terms to the right

15x=-6

x=-6/15

x=-2/5

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