4(4x+1)+4(x=2)

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Solution for 4(4x+1)+4(x=2) equation:



4(4x+1)+4(x=2)
We move all terms to the left:
4(4x+1)+4(x-(2))=0
We multiply parentheses
16x+4x+4-8=0
We add all the numbers together, and all the variables
20x-4=0
We move all terms containing x to the left, all other terms to the right
20x=4
x=4/20
x=1/5

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