4(4x+1)=2(1+6x)+8

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Solution for 4(4x+1)=2(1+6x)+8 equation: 



4(4x+1)=2(1+6x)+8

We move all terms to the left:

4(4x+1)-(2(1+6x)+8)=0

We add all the numbers together, and all the variables

4(4x+1)-(2(6x+1)+8)=0

We multiply parentheses

16x-(2(6x+1)+8)+4=0



We calculate terms in parentheses: -(2(6x+1)+8), so:

2(6x+1)+8

We multiply parentheses

12x+2+8

We add all the numbers together, and all the variables

12x+10

Back to the equation:

-(12x+10)



We get rid of parentheses

16x-12x-10+4=0

We add all the numbers together, and all the variables

4x-6=0

We move all terms containing x to the left, all other terms to the right

4x=6

x=6/4

x=1+1/2

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