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4(4x+1)=3(3x+3)
We move all terms to the left:
4(4x+1)-(3(3x+3))=0
We multiply parentheses
16x-(3(3x+3))+4=0
We calculate terms in parentheses: -(3(3x+3)), so:We get rid of parentheses
3(3x+3)
We multiply parentheses
9x+9
Back to the equation:
-(9x+9)
16x-9x-9+4=0
We add all the numbers together, and all the variables
7x-5=0
We move all terms containing x to the left, all other terms to the right
7x=5
x=5/7
x=5/7
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