4(4x+1)=3x+12

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Solution for 4(4x+1)=3x+12 equation: 



4(4x+1)=3x+12

We move all terms to the left:

4(4x+1)-(3x+12)=0

We multiply parentheses

16x-(3x+12)+4=0

We get rid of parentheses

16x-3x-12+4=0

We add all the numbers together, and all the variables

13x-8=0

We move all terms containing x to the left, all other terms to the right

13x=8

x=8/13

x=8/13

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