4(4x+2)-8(x-2)=3(2x+2)-1

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Solution for 4(4x+2)-8(x-2)=3(2x+2)-1 equation: 



4(4x+2)-8(x-2)=3(2x+2)-1

We move all terms to the left:

4(4x+2)-8(x-2)-(3(2x+2)-1)=0

We multiply parentheses

16x-8x-(3(2x+2)-1)+8+16=0



We calculate terms in parentheses: -(3(2x+2)-1), so:

3(2x+2)-1

We multiply parentheses

6x+6-1

We add all the numbers together, and all the variables

6x+5

Back to the equation:

-(6x+5)



We add all the numbers together, and all the variables

8x-(6x+5)+24=0

We get rid of parentheses

8x-6x-5+24=0

We add all the numbers together, and all the variables

2x+19=0

We move all terms containing x to the left, all other terms to the right

2x=-19

x=-19/2

x=-9+1/2

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