4(4x+2)=8(2x+1)

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Solution for 4(4x+2)=8(2x+1) equation: 



4(4x+2)=8(2x+1)

We move all terms to the left:

4(4x+2)-(8(2x+1))=0

We multiply parentheses

16x-(8(2x+1))+8=0



We calculate terms in parentheses: -(8(2x+1)), so:

8(2x+1)

We multiply parentheses

16x+8

Back to the equation:

-(16x+8)



We get rid of parentheses

16x-16x-8+8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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