4(4x+2-(3-4x))=33x+3(3x-2x)

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Solution for 4(4x+2-(3-4x))=33x+3(3x-2x) equation: 



4(4x+2-(3-4x))=33x+3(3x-2x)

We move all terms to the left:

4(4x+2-(3-4x))-(33x+3(3x-2x))=0

We add all the numbers together, and all the variables

4(4x+2-(-4x+3))-(33x+3(+x))=0



We calculate terms in parentheses: -(33x+3(+x)), so:

33x+3(+x)

We multiply parentheses

33x+3x

We add all the numbers together, and all the variables

36x

Back to the equation:

-(36x)



We add all the numbers together, and all the variables

-36x+4(4x+2-(-4x+3))=0

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