4(4x+3)-6(2-x)-3(2x-1)=19

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Solution for 4(4x+3)-6(2-x)-3(2x-1)=19 equation: 



4(4x+3)-6(2-x)-3(2x-1)=19

We move all terms to the left:

4(4x+3)-6(2-x)-3(2x-1)-(19)=0

We add all the numbers together, and all the variables

4(4x+3)-6(-1x+2)-3(2x-1)-19=0

We multiply parentheses

16x+6x-6x+12-12+3-19=0

We add all the numbers together, and all the variables

16x-16=0

We move all terms containing x to the left, all other terms to the right

16x=16

x=16/16

x=1

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