4(4x+33)=5(x+55)

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Solution for 4(4x+33)=5(x+55) equation: 



4(4x+33)=5(x+55)

We move all terms to the left:

4(4x+33)-(5(x+55))=0

We multiply parentheses

16x-(5(x+55))+132=0



We calculate terms in parentheses: -(5(x+55)), so:

5(x+55)

We multiply parentheses

5x+275

Back to the equation:

-(5x+275)



We get rid of parentheses

16x-5x-275+132=0

We add all the numbers together, and all the variables

11x-143=0

We move all terms containing x to the left, all other terms to the right

11x=143

x=143/11

x=13

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