4(4x+5)+36=21x+15-5x+41

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Solution for 4(4x+5)+36=21x+15-5x+41 equation: 



4(4x+5)+36=21x+15-5x+41

We move all terms to the left:

4(4x+5)+36-(21x+15-5x+41)=0

We add all the numbers together, and all the variables

4(4x+5)-(16x+56)+36=0

We multiply parentheses

16x-(16x+56)+20+36=0

We get rid of parentheses

16x-16x-56+20+36=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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